Ground Engineering Essay Example | Topics and Well Written Essays - 1500 words

Ground Engineering - Essay ExamplePile foundations atomic number 18 chosen for the situations where structures transmit huge dilutes and suitable soil layer capable of supporting these tons ar available only at greater depths. The piles ar long and sl endinger members capable of transmitting the loads of the structure into the hard soil layer or the rocks successfully even if very(prenominal) poor or soft soils that argon considered to be inferior to meet this purpose is present in the upper layers. Based on the load carrying put to work piles atomic number 18 classified as end perambulator pile, friction pile or combination pile that undertakes both the functions appropriately. The friction piles are suitable for the locations where granular soil is present and frictional resistance mingled with the pile and the soil could be utilised in the resistance. While the end bearing piles helps to transmit the entire load a hard stratum through the tip resistance. A sketch of the load action on the end bearing pile and friction pile are shown in the figure 1. The basic structural components of any pile are pile cap and the be of the pile.And (iii) All piles carry only vertical force. ... Figure 1(a) End bearing pileFigure 1 (b) Friction pile (Abebe and Smith, 2005) (Abebe and Smith, 2005)Pile load computationFollowing assumptions are incorporated in the load estimation on piles(i)All piles are considered as rigid (ii) The pile is pinned at the top and bottomAnd (iii) All piles carry only vertical force. The different loads that the pile need to carry would be direct loads from the columns and any other imposed loads on the structure. The direct loads from the columns to the pile are already given in the problem. The other loads are the load from the glass facades and the imposed loads. The glass faade load is the load along the edges of the floor and it could be computed by multiplying the unit load of the faade by the distance between the columns. The de tails of computation is as followsGlass faade load between the columns 1 & 8Distance between the columns 1 and 8 = 20 metre social unit load of facde between the column 1 and 8 = 35 KN/mThe load from the faade is assumed to be transferred equally to both the columns . So the loads are computed as 35 20 / 2 = 350 KNSo the columns 1 and 8 would carry load of 350 KN each from the glass facades.Glass faade load between the columns 4 & 5Distance between the columns 4 and 5 = 20 metreUnit load of facde between the column 4 and 5 = 35 KN/mThe load from the faade is assumed to be transferred equally to both the columns . So the loads are computed as 35 20 / 2 = 350 KNSo the columns 4 and 5 would carry load of 350 KN each from the glass facades placed between the columns 4 and 5.Glass faade load between the columns 1 and 4The columns in this span are 1,2,3